How about:
#!/bin/sh
find -maxdepth 1 -type f -name "*.*" |
sed -e 's/\(.*\)\.\(.*\)/"\1\.\2" "\1"/' |
xargs -r -n2 mv
Padraig.
Gavin McCullagh wrote:
> This is showing my ignorance, but very quickly..
>> if I have 10 files called 1.dat .. 10.dat
>> and I want to do
>> mv 1.dat 1
> ...
> mv 10.dat 10
>> I know I can do the
>> for i in `ls`
> do
> mv XXXXXXXXXXXXXXXXXXXXXXXXX
> done
>> but how do you construct the regexp to extract the first portion from the filename?
> I could do it in perl, I just don't know what the syntax for using this is in the shell (specifically BASH).
Nobody should every need/use perl.
> thanks for your patience
> Gavin
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