That RE also matches
^947,356
so I guess you can only use real live characters/character classes in []
what you really want is
/(^|,)9/
It's only on stroke more,
Fergal
On Wed, May 30, 2001 at 06:28:18PM +0100, Niall O Broin wrote:
> I have a list of numbers in a string like
>>> 123,456,789
>> and I need to find out if any of them begin with 9. This seemed correct
>> #!/usr/bin/perl
> $numlist = $ARGV[0];
> if ($numlist =~ /[,^]9/) {
> print "$numlist matched\n"
> } else {
> print "$numlist didn't match\n"
> }
>> but it doesn't work. Now, I have solved my problem. It's Perl, and TIMTOWTDI
> as we Perlmongers say. I could have split the string, but I chose to do
>> if (",$numlist" =~ /,9/)
>> which works fine. But why won't my program above work ? I had started off
> with
>> if ($numlist =~ /[^,]9/)
>> but realised (in time, believe it or not) that this was of course a negating
> character class. I tried escaping the ^ before I RTFM and simply made the ^
> not the first character, as TFM says to do. I also tried \A instead of ^ but
> although this works outside of a character class, it does not work as above.
>> I just tried this with grep too. Given a file, nums, with these lines
>> 123,987 - MATCH
> 123,456 - NO MATCH
> 987,123 - MATCH
>> I think that grep "[,^]9" nums should match the lines marked MATCH but
> it doesn't. egrep ",9|^9" nums does match the lines marked MATCH so why
> the hell doesn't the alternation work ? What is wrong with my interpretation
> of both the grep and the Perl manuals ? (The alternative is that they're
> both wrong, and that seems passing unlikely).
>>>> Regards,
>>>> Niall
>>>> --
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