Mornin',
Say you were porting some files from dos to linux (woe is me),
and you wanted to run a searh+replace in vi (or sed, or awk or
*shudder* emacs) to convert
#include "foo\bar\apples.h"
to
#include "foo/bar/apples.h"
Now the best i can come up with is this (in vi):
%s/\(#include[^"]*"\)\([^\\]*\)\\\(.*\)/\1\2\/\3/cg
but that will only match and convert the first \. How do I get a regex
to match all the \'s in the line?
Steve
--
"My mom had Windows at work and it hurt her eyes real bad"
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