Anyone got a nice 101 on this ? Or even recommendations for what to read up
on ... pref well-written and online <g>
It's something that's interested me for a while now, but I've never fully
gotten to grips with ...
P
> -----Original Message-----
> On Tuesday 04 June 2002 10:02, John Bolger wrote:
> > Subtract the last number from 256 (in this case 256-248). This gives an
> > answer of 16, which will always be the size of the subnet (including
> > network address and broadcast address).
> > Next get a list in your head of products of this number (in this case
> they
> > will be 0,16,32,48,64, etc.). These are your possible network addresses.
> >
> > At that point is obivious which network your host belongs to (0, as
> > 0<1<15). So your answer is 192.168.0.0
>> This is all wrong of course as 256 -248 is 8 and not 16 ;)
>> So the Subnet ID remains 192.168.0.0 with a broadcast of 192.168.0.7
>> J.
>
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