On Thu, 19 Feb 2004, Padraig Brady wrote:
> OK I've a (very big) file like:
>> 0
> 0
> 1
> 1
> 2
> 2
> 3
> 3
> :
>> I would like to find and print the "2" lines,
> AND THEN STOP PRCOCESSING the humungous file.
awk ' $1 == "2" { lines[i++] = $0 } \
$2 > "2" { exit(); } \
END { for (j=0; j < i; j++) { print lines[j] }'
or somesuch?
> I got as far as sed -n '/2/{p;b};q' but that doesn't deal with the
> case where there are initial lines that don't match.
>> Pádraig.
regards,
--
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