John Allen wrote:
> On Tuesday 06 July 2004 12:00, Paul Jakma wrote:
>>>On Tue, 6 Jul 2004, Philip Reynolds wrote:
>>>>>You need to use a temporary variable, to allow the use of free() or
>>>removal of an element in the list.
>>>>Indeed. the problem is trying to stuff it into the for loop so that
>>macro will still work :)
>>>>>>>#define LIST_LOOP(L, V, N, temp) \
>>> for ((N) = (L)->head; \
>>> (N) && ((temp) = (N)->next); \
>>> (N) = (temp))
>>>>>>Something like the above.
>>>>Nah, that breaks the macro.
>>>>> The correct solution is obviously C++. Macros is bad.
>
What about declaring the function inline ?
inline void LIST_LOOP(list_t * L, list_t ** N){
assert(L);
* N=L->head;
for(; *N ;*N=*N->next)
return;
}
--
Bryan O'Donoghue
Embedded Software Engineer
Europlex Technologies Ltd
Clonshaugh Business & Technology Park
Dublin 17
Ireland
T:+353 (0) 1 2500500
F:+353 (0) 1 2500590
E:bryano at euoplex.ie
W:www.europlex.ie
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