On Thu, Dec 15, 2005 at 11:03:35PM +0000, Braun Brelin wrote:
> Okay,
>> so i'm trying to figure a regular expression to do the following:
>> Take a single (really long) line and break it up into 80 character
> lines. i.e. after every 80th character, insert a newline (or, if it's
> HTML) insert a <br>
fold < file.in > file.out
Not exactly a regex. If you're in vim you can also use the gggqG to wrap
all the lines in the file. gqJ will do the current line.
':set textwidth=80' is the default.
For the <br> I'd pipe it through sed -e 's/$/<br>/'.
Vim line is ':%s /$/<br>/', not exactly what you asked for though.
For perl: 'perl -pe "s/(.{80})/\1\n/g"' works, although it doesn't handle
lines of length 80*n correctly.
perl -pe 's/^(.{80})(.+)/\1\n\2/' will handle it correctly, but you
might need to run it a few times. A while loop on the substitution
should handle that.
Substitute <br> in the above for /n for HTML.
Brian
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