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Colm MacCarthaigh wrote:
| On Fri, Feb 18, 2005 at 11:26:31AM +0000, Bryan O'Donoghue wrote:
||>if((x)!=(y))
|>|>is functionally equivalent to
|>|>if(x==y) return 1; else return 0;
||| No, It certainly is not. And even if it was, it certainly wouldn't be
| equivalent to:
|| if (if(x==y) return 1; else return 0;)
|Am I missing something?
x == y is not the same as x != y
no matter how much syntactic preprocessor sugar you add.
L.
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