[ILUG] integer overflow exception

[Brian Foster]

  | Date: Tue, 5 Jun 2007 21:34:48 +0100
  | From: Colm MacCarthaigh <colm at stdlib.net>
  | 
  |[ ... ] As for Padraig's code, I don't see how random initialisation
  | affects it in the least, why would it matter where i starts?

 It's impossible to be so certain due to a syntax error
 in what was written:  for (;;i++;) ...

 There's an extra semi-colon (‘;’) so we don't know if
 he meant  for (;;i++)  in which case the initial value
 does not matter; or  for (;i++;)  in which case the
 loop will be broken whenever ‘i’ has the value 0 (and
 hence the initial value does matter:  e.g., if 0 is the
 initial value, then the body of the loop will never run).
 ( Also, in the 2nd syntax is meant, there is yet another
  error:  the function falls off the end without returning
  any value, but is declared to return an ‘int’. )

cheers!
	-blf-
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