Hi guys,
I'm trying to come to grips with grep and regular expressions and while I'm making progress, I've come up with some things that puzzle me. Can someone explain to me why grep is returning the following, given the regex I'm using:
[131] ls /data/gps/TEMP
BELF160z.08o BELF.apr dwnld.lst hers1600.08d itrf05_eura.apr lfile.VLNT MACE160z.08n MACE160z.08o MACE208o.08n MACE208o.08o MACE213h.08n MACE213h.08o mace.lst
VLNT160z.08n VLNT160z.08o VLNT213l.08n VLNT213l.08o VLNT.apr vlnt.lst
[132] ls /data/gps/TEMP | grep '^[[:alpha:]]\{4\}[0-9]\{3\}[a-x]\.[0-9]\{2\}[o|n]$'
[133] ls /data/gps/TEMP | grep '^[[:alpha:]]\{4\}[0-9]\{3\}[a-x]\.[0-9]\{2\}[o|n]'
MACE213h.08n MACE213h.08o mace.lst VLNT160z.08n VLNT160z.08o
VLNT213l.08n VLNT213l.08o VLNT.apr vlnt.lst
What I want is an expression that only returns filenames with a specific format: 4 alphabetic characters, followed by 3 numeric, 1 alphabetic (a-x only), a period, 2 numeric characters and an "o" or an "n" at the end. This is what I think line [132] should return, and I don't understand why the first expression doesn't match any of the filenames. I also don't understand why filenames like 'vlnt.lst' are matched following the command in line [133].
The problem seems to be with the [0-9] and I've tried using [[:digit:]] and [\d] instead but neither of those give me the answers I expect either!
Any help appreciated, expecially at 4:30 on a Friday ;-)
Thanks,
Jenny
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