[ILUG] ksh question...

[Braun Brelin]

Thanks.

I just used 2>&1 to redirect.  Being a Perl programmer, I was making things
a bit more complicated (read: elegant) than necessary.  It's still a serious
pain in the ass
though to try and do things with the shell and utilities that I take for
granted in a real
language like Perl.

On this topic, does anyone know how to capture backreferenced vars from a
regexp?

i.e. in Perl it's easy to do:

($a, $b,$c) = foo =~
/(some_stuff_for_a)\s*(some_stuff_for_b)\s*(some_stuff_for_c)/;

I can't find a good way to do this in the shell, however.  I was thinking of
using awk, but
per a previous thread, awk doesn't really support this well.  gawk uses
gensub() but
nawk, mawk, etc. don't support this...

Braun


On Thu, Feb 24, 2011 at 8:33 PM, Francis Daly <francisdaly at gmail.com> wrote:

> On 24/02/2011, Braun Brelin <bbrelin at gmail.com> wrote:
>
> Hi there,
>
> > I'm trying to write a small ksh script that will call mysql (and
> mysqladmin)
> >
> > What I'd like to do is catch the output of mysqladmin and process errors
> > myself
> > rather than have the mysqladmin or mysql command print the errors out on
> > STDERR.
>
> I'm not sure from the question, but are you asking for something other
> than "2> stderr_file", or possibly "2>&1"?
>
> You can fairly easily catch stdout, or stderr, or stdout+stderr, but
> if you want to catch both stdout and stderr, you pretty much need to
> use at least one file.
>
> Hope this helps,
>
>        f
>