[ILUG] ksh question...

[Francis Daly]

On 24/02/2011, Braun Brelin <bbrelin at gmail.com> wrote:

> On this topic, does anyone know how to capture backreferenced vars from a
> regexp?
>
> i.e. in Perl it's easy to do:
>
> ($a, $b,$c) = foo =~
> /(some_stuff_for_a)\s*(some_stuff_for_b)\s*(some_stuff_for_c)/;
>
> I can't find a good way to do this in the shell,

Not a general solution, but for this specific case "set -A bits $line"
may put useful stuff into ${bits[0]} and the like.

Otherwise, I'd probably fall back to something like multiple lines like

  a=$(echo "$line" | grep -o regex_for_a)

but that's because I don't know enough ksh to be sure that there isn't
a better way.

Some languages are better suited to different tasks ;-)

        f