From: John P. Looney (john at domain antefacto.com)
Date: Thu 02 Aug 2001 - 10:32:57 IST
On Thu, Aug 02, 2001 at 12:06:47AM +0100, Conor Daly mentioned:
> The first call to strdup() allocates memory to hold the string and sets
> optionstring to that address. When the second strdup() call passes a
> *new* address to optionstring, what happens the previously allocated
> memory that optionstring *was* pointing to?
No offense Conor, but I strongly recommend you stick to Perl, Shell, TCL
or Java! Something that'll do your garbage collection for you.
In the manpage for strdup, there is;
"Memory for the new string is obtained with mal loc(3), and can
be freed with free(3)"
It should read "For crying out loud, free this as soon as you can, or
you'll be reaching for ElectricFence within a week".
-- When I say 'free', I mean 'free': free from bond, of chain or command: to go where you will, even to Mordor, Saruman, if you desire. " -- Gandalf, paraphrasing the choice between Free and Non-free software
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